Answer:57
Step-by-step explanation:
Conversion factor is
1 US bushel = 4 US pecks
76 rows x 3 pecks= 228 pecks
228 pecks / 4 = 57
Answer: a) 503.2m
b) 621.6m
Step-by-step explanation:
The diagram representing the scenario is shown in the attached photo.
A represents her starting point.
CD = x = how far east she is from her starting point
BC = y = how far south she is from her starting point
Angle BAC = 180 - 129 = 51°
Angle ACD = angle BAC = 51° because they are alternate angles
To determine x, we would apply the cosine trigonometric ratio
Cos 51 = x /800
x = 800Cos51 = 800 × 0.629 = 503.2m
To determine y, we would apply the sine trigonometric ratio
Sin 51 = y /800
y = 800Sin51 = 800 × 0.777 = 621.6m
If Sally paints one room per six hours, she paints 1/6 of the room every hour. Similarly, Steve paints 1/9 of the room every hour. Therefore, together, they paint 1/6+1/9=5/18 of the room every hour. Therefore, it takes the 18/5 of an hour to paint the whole room, since 18/5*5/18=1, so 18/5 of an hour at 5/18 of the room per hour is one room.
Answer:
B.
The solution of |2x + 8| > 6 includes all values that are less than –7 or greater than –1.
The solution of |2x + 8| < 6 includes all values that are greater than –7 and less than –1.
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Step-by-step explanation:
You can find the solution by "unfolding" the absolute value, then dividing by 2 and subtracting 4:
-6 > 2x +8 > 6 . . . . . read this as -6 is less than 2x+8 or 2x+8 is greater than 6
-3 > x +4 > 3 . . . . . . .divide by 2
-7 > x > -1 . . . . . . . . . solution to the first inequality: x is less than -7 or greater than -1.
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The solution to the other inequality is identical, except the direction of the comparison is reversed. It is read differently, because the segments overlap, rather than being disjoint.
-7 < x < -1 . . . . . . . . solution to the second inequality: x is greater than -7 and less than -1.
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These descriptions match choice B.
Answer:
If 0.20 mole of Cl 2 is added to the equilibrium mixture, will the concentration of PCl 5 increase or decrease? If the equilibrium constant for this reaction is expressed in terms of concentrations, written as follows: Here, , and represent the molar concentrations of, , and respectively. Chapter 10, Problem 60CQ is solved.
Step-by-step explanation: