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3 years ago

13

70 miles = ______ kilometers

2 answers:

vampirchik [111]3 years ago

4 0

70 Miles = 112.65408 Kilometers

marysya [2.9K]3 years ago

4 0

1 mile is 1.60934 km,
and 70 miles is 112.654 in kilometers.

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What is 9.423 rounded to the nearest one

MrRa [10]

Answer:

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Step-by-step explanation:

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

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Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

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Substitute values for BC and BA

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$Sin \angle A =\frac{8}{10}$

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Substitute values for AC and BA

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Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

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$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

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3 years ago

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bixtya [17]

Answer:

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Step-by-step explanation:

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2 years ago

Please help show work<br> (Don’t mind my answer I accidentally clicked)<br><br> anything helps :)

Akimi4 [234]

There’s no work for you to show

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3 years ago