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Bezzdna [24]
3 years ago
14

Louise bought 114 pounds of roast beef at $2.00 per pound and ​ 212 ​pounds of turkey at $1.50 per pound. What was her total cos

t? Enter your answer in the box. $
Mathematics
2 answers:
frozen [14]3 years ago
7 0

Answer:

$6.25

Step-by-step explanation:

I did the test

tia_tia [17]3 years ago
5 0
$546.
114 * 2 + 212*1.5
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Katen [24]
What are the instructions or equations to use
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5 0
2 years ago
A flying carpet flies 2.4 miles with the wind in the same amount of time it flies 1.4 miles against the wind. The wind speed is
Citrus2011 [14]

Answer:

15.2 mph

Step-by-step explanation:

2.4÷(x+4)=1.4÷(x-4)

1.4(x+4)=2.4(x-4)

1.4x+5.6=2.4x-9.6

-x=-15.2

x=15.2

Hope this helps!

5 0
2 years ago
In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294
slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

a_4=54 and a_7=1458

To find a_{12}:

The given sequence is a geometric sequence.

The general term of the geometric sequence is a_n=a_1\ r^{n-1}.

If we have 2 terms of a geometric sequence a_n and a_k (n > K),

then we can write the general term as a_n=a_k\ r^{n-k}.

Here we have a_4=54 and a_7=1458.

So, n = 7 and k = 4 ( 7 > 4)

a_7=a_4\ .\ r^{7-4}

1458=54\ . \  r^3

This can be written as

$r^3=\frac{1458}{54}

$r^3=27

$r^3=3^3

Taking cube root on both sides of the equation, we get

r = 3

a_{12}=a_7\ .\ r^{12-7}

     =1458\ .\ r^5

     =1458\ .\ 3^5

a_{12}=354294

Hence the 12th term of the geometric sequence is 354294.

7 0
2 years ago
The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in amb
Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

4 0
3 years ago
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