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lukranit [14]
3 years ago
13

The combined area of the 3 windowpanes and frame shown below is 924 inches squared. The frame is of uniform width. What is the s

ide length, x, of each square windowpane?

Mathematics
2 answers:
Maslowich3 years ago
7 0

Answer:

The sides length x of each square windowpane is 10\ in

Step-by-step explanation:

we know that

924\ in^{2}=(6+3x+6)(6+x+6)\\ \\924=(12+3x)(12+x)\\ \\924=144+12x+36x+3x^{2}\\ \\ 3x^{2}+48x- 780=0

Solve the quadratic equation

using a graphing tool

The solution is x=10\ in

see the attached figure

Zinaida [17]3 years ago
3 0

Answer:

10 inches is the side length of each square windowpane.

Step-by-step explanation:

Length of the single window plane = x

Width of the single window plane = x

On combining all the windows pane ,length becomes , l= 3x

On combining all the windows pane ,width becomes , b= x

Length of the frame = L = 6 + 3x+ 6 = 12 + 3x

Width of the frame = B = 6 + x+ 6 = 12 + x

Area of the frame, A = L × B = (12+3x)\times (12+x)

Given sum of combined area of the 3 windowpanes and frame = 924 inch^2

a + A=924

(12+3x)\times (12+x)=924

144+48x+3x^2=924

3x^2+48x-780=

x^2+16x-260=0

x^2+26x-10x-260=0

x(x+26)-10(x+26)=0

(x+260)(x-10)=0

x = 10 (accept)

x  = -26 (reject)

10 inches is the side length of each square windowpane.

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dezoksy [38]

Answer:

12 square inches.

Step-by-step explanation:

Please consider the complete question.

A model ship has a mast that is 7 inches tall. A right triangular sail goes from the top of the mast to 1 inch from the bottom of the mast. The length of the base of the sail is 4 inches. The height of the sail is along the mast. Find the area of the sail.

The sail will form a right triangle with respect to mast, whose height is 6 inches and base is 4 inches as shown in the diagram.

The area of the sail will be equal to area of triangle.

\text{Area of triangle}=\frac{1}{2}(\text{Base}\times\text{Height})

\text{Area of triangle}=\frac{1}{2}(4\text{ in}\times6 \text{in})

\text{Area of triangle}=2\text{ in}\times 6 \text{in})

\text{Area of triangle}=12 \text{ in}^2

Therefore, the area of the sail is 12 square inches.

6 0
3 years ago
PLEASEE helpppp correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!
dolphi86 [110]

Answer:

126?? i think

Step-by-step explanation:

A triangle always ahs a total of 180 degrees, so I added 24+28+6= 54, then subtracted it by 180 and got 126

(Dont fully trust me, im not an expert in geometry :P)

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3 years ago
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3 years ago
Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )
Gemiola [76]

QUESTION 1

The given inequality is

|m|-2>0

We group like terms to get,

|m|>2


This implies that,

-m>2 or m>2.

We simplify the inequality to get,

m or m>2.

We can write this interval notation to get,

(-\infty,-2)\cup (2,+\infty).


QUESTION 2

|x-4|-3\:>\:5.

We group like terms to get,


|x-4|\:>\:5+3.


|x-4|\:>\:8

We split the absolute value sign to get,

-(x-4)\:>\:8 or x-4\:>\:8


This implies that,


x-4\: or x-4\:>\:8


x\: or x\:>\:8+4


x\: or x\:>\:12


We can write this interval notation to get,

(-\infty,-4)\cup (12,+\infty).


QUESTION 3

The given inequality is

|6+9x|\leq 24


We split the absolute value sign to obtain,

-(6+9x)\leq 24 or (6+9x)\leq 24


This simplifies to

6+9x\ge -24 and 6+9x\leq 24


9x\ge -24-6 and 9x\leq 24-6


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x\ge -\frac{10}{3} and x\leq 2

-\frac{10}{3}\leq x\leq2

We write this in interval form  to get,

[-\frac{10}{3},2]


QUESTION 4

The given inequality is

|1-5a|>29

We split the absolute value sign to get,

-(1-5a)>29 or 1-5a>29

This simplifies to,

1-5a\: or 1-5a\:>\:29


This implies that,

-5a\: or -5a\:>\:29-1


-5a\: or -5a\:>\:28


a\:>\:6 or a\:

We write this in interval notation to get,

(-\infty,-\frac{28}{5})\cup (6,+\infty)















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