Here’s the answer. See pictures.
Plz help I’m you guessed it desperate
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<u>Answer:</u>
<u>Solution:</u>
Given: x=30
To solve:
On substituting the value of x,
On dividing 30 and 5 we get,
So, the option is 15.
Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place -
Number of ways for second place -
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place -
Number of ways for second place -
Total number of different tickets are possible is
Therefore, 4032 different tickets are possible.