Answer:
The y-value is -20
Step-by-step explanation:
So let's solve this by Elimination method;
-2(4x + 5y = -12)
4(2x + 3y = -16)
Let's Distribute;
-8x - 10y = 24
8x + 12y = -64
So x cancels out because -8 + 8 = 0
-10y + 12y = 2y
24 - 64 = -40
2y = -40
Divide both sides by 2;
y = -20
Now lets plug in y to find the value of x;
4x + 5(-20) = -12
4x - 100 = -12
Add 100 to both sides;
4x = 88
Divide both sides by 4;
x = 22
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
It’s 90 degrees hope this helps
Answer:3
Step-by-step explanation:
One such line is y = -8/7x + 3 (The perpendicular slope will be the negative reciprocal of the given slope. You can graph it to make sure.)
Hope this helps!
Brainliest Please!
