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3 years ago

PLEASE HELP WILL MARK AS BRAINLIEST

Mathematics

1 answer:

AveGali [126]3 years ago

5 0

Answer:

$\boxed{\bold{\huge{\boxed{Area\ of\ Trapezium = 150\ cm\²}}}}$

Step-by-step explanation:

Using Pythagorean Theorem first to find EC

$\sf CB^2 = EB^2+EC^2\\Where \ CB = 13 \ and \ EB = 5 \\13^2 = 5^2 + EC^2 \\169 - 25 = EC^2 \\EC^2 = 144\\Taking \ sqrt \ on \ both \ sides\\EC = 12 \ cm$

Given that:

AE = EC

AE = 12 cm

Now,

AB = AE + EB

AB = 12 + 5

AB = 17 cm

ABCD is a trapezoid / trapezium

So,

Area of Trapezium = $\sf \frac{AB+DC}{2} (EC)$

Where AB = 17 , DC = 8 and EC = 12

Area of Trapezium = $\sf \frac{17+8}{2} ( 12)$

Area of Trapezium = (25)(6)

Area of Trapezium = 150 cm²

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Question in image. :)

quester [9]

a. f(a) =5a+12

we have 1. a=6

Therefore, where ever we find a we'll substitute in 6

f(6) =5(6) +12

6f=30+12

6f=42

so therefore 1. a=6 will match c on the right

2. a=2

f(2) =5(2) +12

2f = 10+12

2f = 22

therefore 2. a=2 will match a on the right

3. a=4

f(4) =5(4) +12

4f=20+12

4f=32

therefore 3. a=4 will match d on the right

4. a=5

f(5) =5(5) +12

5f=25+12

5f=37

therefore 4. a=5 will match b on the right

7 0

3 years ago

What is the solution of each proportion? 4/9=m/54

Alex

It is M=24 your welcome

4 0

3 years ago

Read 2 more answers

Please help! I've already answered part a, I don't understand what part b is asking.

Luba_88 [7]

Step-by-step explanation:

So, there is something known as a removable discontinuity, and it's essentially where you can define f(x) using the most simplified fraction, where you could normally not define f(x).

So we have the following equation:

$f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}$

As you may know, we cannot divide a number by the value of zero. When the denominator is equal to zero, on the graph this will appear as a vertical asymptote, where x approaches the value that makes the denominator zero, but never actually reaches it.

If you look at each denominator, you can set them equal to zero to find the vertical asymptotes

x+1 = 0

x=-1

There should be a vertical asymptote at x=-1, since it would make two of the denominators equal to -1, but let's divide the two fractions first.

Original Equation

$f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}$

Keep, change, flip

$f(x) = (\frac{x+5}{x+1}*\frac{(x-4)(x+1)}{(x+3)(x-2)})-\frac{1}{x-2}$

Multiply the two fractions

$f(x) = (\frac{(x+5)(x-4)(x+1)}{(x+1)(x+3)(x-2)})-\frac{1}{x-2}$

Notice how the x+1 is in the numerator and fraction? That means we can cancel it out!

$f(x) = (\frac{(x+5)(x-4)}{(x+3)(x-2)})-\frac{1}{x-2}$

In this simplified version of the fraction, we can technically define f(-1), but in the original version, since it's not defined there is a removable discontinuity at x=-1, meaning there is no vertical asymptote, but the function is still not defined at f(-1), and there will be a hole at that point.

4 0

2 years ago

A fraction closest to 2/3

SIZIF [17.4K]

Answer:

4/6

Step-by-step explanation:

4/6 because if u simplify it would be 2/3 and 2/3 is 0.66666666. also 4/6 is 0.66666666

3 0

4 years ago

Suppose that extra fingers and toes are caused by a recessive trait, but it appears in only 60% of homozygous recessive individu

Ket [755]

Answer:

0.15 = 15%

Step-by-step explanation:

Let's call the recessive allele x, and the dominant allele X.

The homozygotes have the pair xx, and the heterozygotes have the pair Xx.

If two heterozygotes conceive a child, there are four configurations that the child can have:

xx, xX, Xx, XX

the only configuration that allows the child the possibility to have extra fingers and toes is the xx, as this aspect is a recessive trait, so the probability of the child being xx is 25% (1 option between 4 options, all of them with equal probabilities).

If the child is xx, there is a chance of 60% of the child having extra fingers and toes. So, the final probability is:

25% * 60* = 0.25 * 0.6 = 0.15 = 15%

8 0

4 years ago