All categories

2 years ago

What is the slope intercept form for y-5=3(x-3)

Mathematics

1 answer:

zubka84 [21]2 years ago

4 0

Answer:y=3x-4

Step-by-step explanation:

you add 5 on both sides

simplify

and get y on one side

slope is 3

the y intercept is -4

You might be interested in

Which of the following are exterior angles?

Bas_tet [7]

Answer: B

Step-by-step explanation: An exterior angle is an angle that exceeds 90 degrees (2,3) but not a straight line

3 0

3 years ago

A class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an A on the test, and 35% o

erica [24]

.78 rounded to the nearest hudredth as asked in the orignal question. You are welcome! :)

8 0

3 years ago

Read 2 more answers

How to do an angle of impact

oksian1 [2.3K]

Answer:

Measure the length and width of the splatter. Divide the width of the splatter by its length.

5 0

3 years ago

A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume t

sladkih [1.3K]

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

$\frac{dy}{dt}\ \alpha\ y(1-y)$

$\frac{dy}{dt}=ky(1-y)$

where k is the constant of proportionality, dy/dt = rate at which the rumor spreads

$\frac{dy}{dt}=ky(1-y)\\\frac{dy}{y(1-y)}=kdt\\\int\limits {\frac{dy}{y(1-y)}} \, =\int\limit {kdt}\\\int\limits {\frac{dy}{y}} +\int\limits {\frac{dy}{1-y}} =\int\limit {kdt}\\\\ln(y)-ln(1-y)=kt+c\\ln(\frac{y}{1-y}) =kt+c\\taking \ exponential \ of\ both \ sides\\\frac{y}{1-y} =e^{kt+c}\\\frac{y}{1-y} =e^{kt}e^c\\let\ A=e^c\\\frac{y}{1-y} =Ae^{kt}\\y=(1-y)Ae^{kt}\\y=\frac{Ae^{kt}}{1+Ae^{kt}} \\at \ t=0,y=10\%\\0.1=\frac{Ae^{k*0}}{1+Ae^{k*0}} \\0.1=\frac{A}{1+A} \\A=\frac{1}{9} \\$

$y=\frac{\frac{1}{9} e^{kt}}{1+\frac{1}{9} e^{kt}}\\y=\frac{1}{1+9e^{-kt}}$

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

$y=\frac{1}{1+9e^{-0.8959t}}\\0.75=\frac{1}{1+9e^{-0.8959t}}\\t=3.68\ days$

5 0

3 years ago

ASAP math help algebra plzzz

skelet666 [1.2K]

This is a geometric sequence because each term is a constant multiple, called the common ratio, of the previous term. In this case the common ratio, noted as "r", is:

8/-2=-32/8=128/-32=r=-4

The first term is -2

Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.

Since we know r and a for this problem already we can say:

a(n)=-2(-4)^(n-1)

6 0

3 years ago