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Bad White [126]
3 years ago
13

15 points! What is the scale factor of the dilation?

Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer: \frac{1}{2}

Step-by-step explanation:

Use the formula for calculate the distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Calculate the distance AB. Substitute the coordinates into the formula. Then:

d_{AB}=\sqrt{(8-0)^2+(8-(-7))^2}

d_{AB}=17

Calculate the distance A'B'. Substitute the coordinates into the formula. Then:

d_{A'B'}=\sqrt{(2-6)^2+(1-5-(-6))^2}

d_{A'B'}=\frac{17}{2}

As you can see, the distance A'B' is the distance AB multiplied by 1/2. Therefore, this is the scale factor.

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alisha [4.7K]

Answer:

V≈4624.42

Step-by-step explanation:

4 0
3 years ago
For every 15 Cheetos I ate 300 calories what's the unit rate
gregori [183]

Answer:

20 calories per Cheetos

Step-by-step explanation:

hope it helped

5 0
3 years ago
I need some help please
ExtremeBDS [4]
Using the law of cosins

sin(angle) = Opposite Leg / Hypotenuse

The angle is given as 35 degree and the hypotenuse is given as 30 feet.

Sin(35) = X ( opposite leg) / 30

X = 30 * sin(35)

x = 17.2 feet.

Total height = 17.2 + 6.5 = 23.7, round to 24 feet.

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6 0
3 years ago
Graded Assignment
san4es73 [151]

Answer:

1.) Amount of potting soil purchased last week.

2) 2p + 4 = 28

3.) 12 lbs

Step-by-step explanation:

1.) The unknown information is what we intend to find out using the information given, which is the amount of potting soil Emmanuel bought last week.

2.)

Let amount of potting soil bought last week = p

Amount bought this week = 2p + 4

Since amount bought this week = 28

Hence, we have ;

28 = 2p + 4

28 - 4 = 2p

24 = 2p

p = 24 / 2

p = 12

8 0
3 years ago
(1+tan^2 A)cot A/cosec^2 A= tanA​
Rufina [12.5K]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

1 + tan²A = sec²A , secA = \frac{1}{cosA}, cosecA = \frac{1}{sinA} , cotA = \frac{cosA}{sinA} , tanA = \frac{sinA}{cosA}

Consider the left side

\frac{(1+tan^2A)cotA}{cosec^2A}

= \frac{sec^2AcotA}{cosec^2A}

= \frac{\frac{1}{cos^2A}(\frac{cosA}{sinA})  }{cosec^2A}

= \frac{\frac{1}{cosAsinA} }{\frac{1}{sin^2A} }

= \frac{1}{cosAsinA} × sin²A

= \frac{sinA}{cosA}

= tanA = right side , thus proven

4 0
2 years ago
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