<span><span>1. </span>Couches = $4 000
Reclining Chairs = $ 2 040
=> Loveseats = $2 800
So, the luxury store went on sale that makes each prices divided 4
=> Couches = 4 000 / 4 = 1 000 dollars
=> 2 couches = 2 000 dollars
=> reclining chairs = 2 040 / 4 =510 dollars
=> 1 reclining chair = 510 dollars
=> Loveseats = 2 800 / 4 = 700 dollars
=> 3 loveseats = 2 100 dollars</span>

8 0

3 years ago

How to solve for the shaded region

k0ka [10]

The shaded region is a triangle. Triangle area can be determined with formula
a = 1/2 × b × h

From the question, we know that the triangle consists of
base = 10 - 6 = 4 m
and the height is the dimension which is perpendicular to the base,
height = 6 m

Find the triangle area
a = 1/2 × b × h
a = 1/2 × 4 × 6
a = 1/2 × 24
a = 12

The area of the shaded region is 12 m²

5 0

3 years ago

A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte

allsm [11]

Answer:

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

$E_i = \frac{100}{5}= 20$

The statsitic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0

3 years ago