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Greeley [361]
3 years ago
9

Find the total surface area of the square pyramid in the figure. thanks!!

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

B: 144 yd²

Step-by-step explanation:

It's a square pyramid : Base area 8 x 8 = 64

4 side area:((8 x5) /2) x 4 = 80

Total area: 64 +80 = 144

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Please help. don’t understand :((
Greeley [361]

Answer:

Step-by-step explanation:

place x = 19

f(19) = 3 / 19 + 2 - Sqrt 21 - 3

= 3/21 - 4

= - 81/21

= - 27/7

8 0
2 years ago
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the sides of a triangle are 8 inches, 9 inches, and 10 inches. if the shortest side of a similar triangle is 24 inches Find long
shutvik [7]
The answer is 30 inches:)

7 0
3 years ago
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If the first chapter of a certain book is 40 pages long and makes up 20% of the book, how many pages does the entire book have?
Setler [38]

Answer:

200

Step-by-step explanation:

20% of a book = 40 pages

100% of a book = x pages

20/100 = 40/x                Cross multiply

20x = 100*40                 Combine the right

20x = 4000                    Divide by 20

20x/20 = 4000/20         Do the division

x = 200                           Answer

5 0
3 years ago
If there are 6 serving in a 2/3 pound lb package of pound is in each serving
Serhud [2]

Answer:

\boxed{\math{\frac{1}{9}\text{ lb}}}

Step-by-step explanation:

\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}

\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}

3 0
3 years ago
Example 2
PIT_PIT [208]

Answer: (a) 314.2cm², (b) 157.1cm², (c) 78.55cm² (e) 6.77

Step-by-step explanation: (a)  Area of the circle with radius of 10 cm = πr²

                                                                          = 3.142 × 10 × 10

                                                                          = 3.142 × 100

                                                                          = 314.2cm²

The formula                                                       = πr²

(b)  Area of the half of a circle known as semicircle

                                                                         = πr²/2

                                                                         = 3.142 ×10 × 10/2

                                                                         = 3.142 × 50

                                                                         = 157.1cm²

The formula                                                      = πr²/2

(c)  A quarter of a circle is called quadrant

                                                            = πr²/4

                                                            = 3.142 × 10 × 10/4

                                                            = 314.2/4

                                                            = 78.55cm²

The formula is written thus = πr²/4, which implies that the circle is divided into 4 unit

(d) The conjecture about how to determine the area of the sector is

Formula of a sector = ∅/360(πr²)

<u>Information</u>

The arc  cant be 60°, therefore information incomplete.

(e) Area of the sector with the angle AOB of 60° = 24.

To find the radius of the angle, make v the subject of the formula from the formula.

Sector area = πr²∅/360°

equate formula to 24.

Therefore πr²∅/360° = 24

Multiply through by360° to make it a linear expression

It now becomes πr²∅ =24× 360°

                                                     r² = 24  x 360/π × ∅°

                                                     r² = 24 × 360° /3.142 × 60°

                                                     r² = 3,640/188.52

                                                     r² = 45.8

To find r , we take the square root of both side by applying laws of indicies

                                    Therefore r = √45 .8

                                                      r = 6.77

(f)   General formula = ∅°/360° × (πr²)

angle substended at centre by the arc = x°

assuming the radius of the circle = ycm, Therefore,  area of the sector = { ∅°/360° × πy² }

                                                     

                                                   

8 0
3 years ago
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