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Wewaii [24]
3 years ago
10

Rachel spent $300 more than Samuel. If Rachel spent $743, then how much did Samuel spend?

Mathematics
1 answer:
defon3 years ago
4 0

Answer:

$443

Step-by-step explanation:

743-300=443.

Hope this helps you :)

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Find the number described. What number is 16​% of 70​?
photoshop1234 [79]

Answer:

58.8

Step-by-step explanation:

multiply 16% by 70 then substract your answer by 70

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URGENT! find the sum. the answer is not D​
otez555 [7]
<h3>Answer:  C)  -1/2</h3>

=============================================

Explanation:

We'll apply the derivative to get

g(x) = 4x^3 + 3x^2

g ' (x) = 3*4x^2 + 2*3x

g ' (x) = 12x^2 + 6x

Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.

g ' (x) = 0

12x^2 + 6x = 0

6x(2x + 1) = 0

6x = 0 or 2x+1 = 0

x = 0 or x = -1/2

Adding those two said solutions yields us the final answer choice C

7 0
3 years ago
What is the quotient of 75 divided by 5
Sav [38]

Answer:

15

Step-by-step explanation:

75/5 equals 15

this that when 15 is multiplied 5 times, it equals 75

therefore the answer is 15

7 0
2 years ago
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Does anyone know how to substitute -2 into this equation -2x + ( 12 - 9 ) = 2 + 9 + -2x
alexandr1967 [171]

Answer:

-2(-2) + (12-9) = 2 + 9 + -2(-2)

Step-by-step explanation:

6 0
3 years ago
Whats the roots of the following three problems:
klemol [59]

QUESTION 1

The given function is

f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}

We simplify to get;

f(x)=\frac{x-3}{x+2}

This function is equal to zero when x-3=0

\Rightarrow x=3

QUESTION 2

The given function is

f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}

f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}

We factor to get;

f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}

f(x)=\frac{5(x-1)}{(2x-3)}

This function equals zero when

5(x-1)=0

x=1

QUESTION 3

The given function is

f(x)=\frac{x^3-8}{x^2-6x+8}

We factor to get,

f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}

f(x)=\frac{x^2+2x+4}{x+4}

The function equals zero when x^2+2x+4=0

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D=2^2-4(1)(4)

D=-12

Hence the equation has no real roots.

The complex roots are

x=-\sqrt{3}i-1 or x=-1+\sqrt{3}i

4 0
3 years ago
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