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slava [35]
3 years ago
13

What is the length of the side opposite the 60 degree angle?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0
My guess is 30 because every triangle has to add up to 180. 90+60 is 150 180-150 is 30
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1.4 plus what equals 0.9
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Answer: 2.3

Step-by-step explanation:

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Step-by-step explanation:

becuase it says "Henry's cousin is a member of the choir."

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For each initial value problem, determine whether Picard's Theorem can be used to show the existence of a unique solution in an
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Part a: f , \, f_y is continuous at the initial value (0,0) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Part b: f_y is not continuous at the initial value (0,0) so due to Picardi theorem there does not exist an interval such that the IVP has a unique solution.

part c: f , \, f_y is continuous at the initial value (0,1) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Step-by-step explanation:

Part a

as y^{' }=ty^{4/3}

Let

f(t,y)=ty^{4/3}

Now derivative wrt y is given as

f_y=\frac{4}{3}ty^{1/3}

Finding continuity via the initial value

f is continuous on R^2 also f_y is also continuous on R^2

Also

f , \, f_y is continuous at the initial value (0,0) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Part b

as y^{' }=ty^{1/3}

Let

f(t,y)=ty^{1/3}

Now derivative wrt y is given as

f_y=\frac{1}{3}ty^{-2/3}

Finding continuity via the initial value

f is continuous on R^2 also f_y is also continuous on R^2

Also

f_y is not continuous at the initial value (0,0) so due to Picardi theorem there does not exist an interval such that the IVP has a unique solution.

Part c

as y^{' }=ty^{1/3}

Let

f(t,y)=ty^{1/3}

Now derivative wrt y is given as

f_y=\frac{1}{3}ty^{-2/3}

Finding continuity via the initial value

f is continuous on R^2 also f_y is also continuous on R^2 when y\neq 0

Also

f , \, f_y is continuous at the initial value (0,1) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

6 0
3 years ago
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