The answer is A. y=-3/2x-6
(a) The maximum height of the ball above the ground is 12.5 m and the time of motion is 1.43 s.
(b) The time taken for the ball to contact the other player at 0.5 m above the ground is 3.0 s.
<h3>Maximum height reached by the ball</h3>
The maximum height reached by the ball is calculated as follows.
At maximum height, the final velocity, v = 0
dh/dt = v = 0
dh/dt = -2(4.9)t + 14
0 = -9.8t + 14
9.8t = 14
t = 1.43 s
H(1.43) = -4.9(1.43)² + 14(1.43) + 2.5
H(1.43) = -10.02 + 20.02 + 2.5
H(1.43) = 12.5 m
<h3>Time to reach maximum height</h3>
12.5 = -4.9t² + 14t + 2.5
4.9t² - 14t + 10 = 0
t = 1.43 s
<h3>Time for the ball to reach 0.5 m above the ground</h3>
0.5 = -4.9t² + 14t + 2.5
4.9t² - 14t + - 2 = 0
t = 3.0 seconds
The complete question is below:
In a volleyball match Hanein serves the volleyball at 14 m/s, from a height of 2.5 m above the court. The height of the ball in flight is estimated using the equation, h = -4.9t² + 14t + 2.5, where t is the time in second and h is height above ground, in metres.
Learn more about time of motion here: brainly.com/question/2364404
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Answer:
its scale factored by 6
Step-by-step explanation:
Answer:
1a. 0.5291
1b. 2.0370
1c. 4.2661
2a. 25.7693
2b. 1.8665
2c. 24.0420
2d. 5
Step-by-step explanation:
sin(34) = 0.5290826861 ≈ 0.5291
12 tan(63) = 2.036997025 ≈ 2.0370
5 cos(56) = 4.2661005386 ≈ 4.2661
2a. You have to use tan because tan is opposite over adjacent.
You have 
You have to use inverse tangent.
2b. You have to use cos because cos is adjacent over hypotenuse.
You have 
0.2666429324 = 
x = 1.8665005268 ≈ 1.8665
2c. You have to use sin because sin is opposite over hypotenuse.
2d. Use the pythagorean theorem.
5
Answer:
751.124
Step-by-step explanation:
area of a cricle is
πr^2
take π to be 22÷7
A= πr^2
A=22÷7*15*15
A=22÷7*225
7 divides 225
= 34.142
22*34.142
A= 751.124
