Answer:
HA = 16.2 m
DE = 17 m
Step-by-step explanation:
From the base of the cuboid, HDA will form a right angle triangle, where;
DA = 15 m
HA = 6 m
HA is the hypotenuse
Using pythagoras theorem;
HA = √(15² + 6²)
HA = √(225 + 36)
HA = √261
HA = 16.155 m
Approximating to 1 decimal place gives;
HA = 16.2 m
Similarly, HDE will also form a right angle triangle.
Thus;
DE = √((HD)² + (HE)²)
HD = 16.2 m
HE = 5 m
Thus;
DE = √(16.2² + 5²)
DE = 16.95 m
Approximating to 1 decimal place gives
DE = 17 m
The Answer should be 0.12
Answer:
5+2y=13 is linear
y=+7 is linear
y-5=2(x-1) is linear
=x+7 idk this is not complete so i cant answer it
x=-4 is linear
HOPE IT HELPED<3 tell me if I am wrong.
Step-by-step explanation:
The answer is thirty-six. 36.
<u>ANSWER</u>
The zeros are ![x=-5,x=0,x=5](https://tex.z-dn.net/?f=x%3D-5%2Cx%3D0%2Cx%3D5)
EXPLANATION
Given;
.
We can rewrite the function as
![f(x)=x^2(x^2-25)](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%28x%5E2-25%29)
![\Rightarrow f(x)=x^2(x^2-5^2)](https://tex.z-dn.net/?f=%5CRightarrow%20f%28x%29%3Dx%5E2%28x%5E2-5%5E2%29)
![\Rightarrow f(x)=x^2(x-5)(x+5)](https://tex.z-dn.net/?f=%5CRightarrow%20f%28x%29%3Dx%5E2%28x-5%29%28x%2B5%29)
The zeros are found by equating the function to zero.
![\Rightarrow x^2(x-5)(x+5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%28x-5%29%28x%2B5%29%3D0)
![\Rightarrow (x-5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-5%29%3D0)
The multiplicity is 1, since it is odd the graph crosses at this intercept. which is ![x=5](https://tex.z-dn.net/?f=x%3D5)
Or
![\Rightarrow (x+5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x%2B5%29%3D0)
The multiplicity is 1, since it is odd the graph crosses at this intercept. which is ![x=-5](https://tex.z-dn.net/?f=x%3D-5)
Or
![\Rightarrow x^2=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%3D0)
This last root has a multiplicity of 2.
That is
repeats two times.
Since the multiplicity is even, the graph touches the x-axis at the point
.
See graph.