Please help me I WILL REPORT YOU FOR A LINK OR UNHELPFUL ANSWER i give brainliest

What is the solution set of the equation x ^ 2 - 3x - 10 = 0 ? pls show work

Yanka [14]

Answer:

Factors :- (x - 5) (x + 2)

Values :- x = 5, x = -2

Step-by-step explanation:

= > x^2 - 3x - 10 = 0

= > x^2 - (5 - 2)x - 10 = 0

= > x^2 - 5x + 2x - 10 = 0

= > x (x - 5) + 2 (x - 5) = 0

= > (x + 2) ( x - 5) = 0...factors

= > x = 5, - 2...values

<h2>Hope it helps you!! </h2>

7 0

2 years ago

What answer is this?

klemol [59]

Answer:

option B

$\frac{31}{50}-\frac{4}{25} i$

Step-by-step explanation:

Given in the question a complex fraction

To divide complex numbers, you must multiply by the conjugate. To find the conjugate of a complex number all you have to do is change the sign between the two terms in the denominator.

$\frac{5+4i}{6+8i}(\frac{6-8i}{6-8i})$

Distribute (or FOIL) in both the numerator and denominator to remove the parenthesis.

$\frac{30+24i-40i-32i²}{36-64i^{2} }$

Simplify the powers of i, specifically remember that i² = –1.

$\frac{62-16i}{36+64}$

$\frac{62}{100}-\frac{16i}{100}$

simply

$\frac{31}{50}-\frac{4}{25}i$

8 0

3 years ago

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

2 years ago

-4x+2y=5 is this in a standard form

soldier1979 [14.2K]

Right. Your answer is still no because your x-value needs to be positive.

8 0

3 years ago

An equation is shown below:

IrinaK [193]

5(2x - 8) + 15 = -15
-15 -15 subtract 15 from each side
5(2x - 8) = -30
÷5 ÷5 divide both sides by 5
2x - 8 = -6
+8 +8 add 8 to each side
2x=2
÷2 ÷2 divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15 Correct! x=1

7 0

3 years ago

Read 2 more answers