The first one would be 1 dash after the last one. The second one would be in the middle of the 3rd and 4th dash, the 3rd would b at 2. The fourth would b slightly after the 1st dash after 3. And the last would be in the middle of the 1st dash after 2.5 and the 2nd
The sum of the volume of its part
The solution for this problem is:It's given that the heights are normally distributed.
5 feet 7 inches = (5*12 +7) inches = (60+7) inches = 67 inches.
The z-score is (67 - 69.1)/(2.65) = -1.136. The probability is 0.127978 or 12.8%, making probability of a height over 67 inches
Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm
now, write the question as a system of equations
3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300
now you have a system of equations
3x+2y =200
4x+4y =300
solve for x and y
i think it is 60 because 30 divided by 3-4 equals 2Step-by-step explanation: