<span>25 is 50% of 49.99
..................................</span>
Using it's concept, it is found that the probability of being a girl and choosing lemonade is given by:
b. 0.2.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, out of 130 people, 26 are girls who choose lemonade, hence the probability is given by:
p = 26/130 = 0.2, which means that option b is correct.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
The test statistic needed to evaluate the claim is t = -1.08.
Step-by-step explanation:
The test statistic is:
In which X is the sample mean, 
is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.
At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.
This means that 
Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.
This means that 
What is the test statistic needed to evaluate the claim?
The test statistic needed to evaluate the claim is t = -1.08.
A square is a rhombus, but a rhombus is not always a square
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
