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denis-greek [22]
3 years ago
7

A rocking horse has a weight limit of 60 pounds .What weight is 95 percent of the limit?

Mathematics
2 answers:
Eduardwww [97]3 years ago
4 0

Answer:

57 pounds is 95 percent of the limit.

Step-by-step explanation:

Given the statement: A rocking horse has a weight limit of 60 pounds.

⇒Weight limit of rocking horse  = 60 pounds.

To find what weight is 95 percent of the limit.

Let x be the weight.

then;

x = 95% of 60

x = \frac{95}{100} \times 60

or

x = \frac{95 \times 60}{100} = \frac{5700}{100} = 57

therefore, 57 pounds is 95 percent of the limit.


fiasKO [112]3 years ago
3 0

Answer:

57 pounds weight is 95 percent of the limit .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

As given

A rocking horse has a weight limit of 60 pounds .

Here

Percentage = 95%

Total value = 60 pounds

Put in the formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

95 = \frac{Part\ value\times 100}{60}

Part value = \frac{95\times 60}{100}

Part value = \frac{5700}{100}

Part value = 57 pounds

Therefore 57 pounds weight is 95 percent of the limit .




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