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fomenos2 years ago

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Consider circle O. If AE = 7, EC = 2, and BE = 4, what is ED?

miv72 [106K]

The correct answer is 3.5

Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.

Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)

The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?

To solve for ED, we simply substitute the known values into the equation
$ED = \frac{7(2)}{4} = \frac{14}{4} = 3.5$

6 0

3 years ago

Read 2 more answers

Can someone please help me with this?

geniusboy [140]

Answer: B and D

Step-by-step explanation:

First, solve the terms inside of the parenthesis. As a general rule, whenever you multiply two terms that have the same base, you can add their exponents.

Applying this rule, the base in the problem is 6, and the exponents are 3 and -4. The sum of 3 and -4 leaves -1. Therefore, this is one of our solutions:

$(6^-^1)^-^3$

When you have an exponential term raised to another exponent, you can simply multiply the exponents. In the previous solution given above, multiply -1 and -3 to get 3. Therefore our second solution is:

$6^3$