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3 years ago

At what point does the line with equation y=4-2x cut the y axis?

Mathematics

1 answer:

Mila [183]3 years ago

7 0

Answer:

Step-by-step explanation:

This equation is in a reversed form of slope-intercept, or y=mx+b. In this form, b is the y-intercept and in the equation b is equal to 4 and the slop is 2!

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PLS HEPP QUICK... Solve -2,6 and 0,4 using slope then use your answer and one of the points to right the equation in point slope

Ainat [17]

Answer:

-1

Step-by-step explanation:

rule:

y2- y1 over x2 - x1

so,

y2= 4

y1= 6

x2= 0

x1= -2

4 - 6 over 0-(-2)

= -1

3 0

3 years ago

In a video game, Conner scored 25% more points than Max. If c is the number of points that Conner scored and m is the number of

Elden [556K]

Answer:

D. c=m+0.25m

Step-by-step explanation:

Connor score is 25% more than Max's score so for the equation you need to find what 25 percent of that answer is and then add it to Maxs score to find the total.

4 0

3 years ago

Simplify this question

Serhud [2]

Step-by-step explanation:

9x²/3x + 12x/3x + 1

= 3x/1 + 4/1 + 1

= 3x + 5

I hope this is true..

8 0

2 years ago

Read 2 more answers

Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form

nadya68 [22]

Answer:

$y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (15,2.2) and (5,1.6):

$m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}$

Therefore, the slope of the line is $\frac{\displaystyle 3}{\displaystyle 50}$ . Plug this into $y=mx+b$ :

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

2) Determine the y-intercept (b)

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

Plug in a given point and solve for b:

$1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b$

Therefore, the y-intercept is $\frac{\displaystyle 13}{\displaystyle 10}$ . Plug this back into $y=\frac{\displaystyle 3}{\displaystyle 50}x+b$ :

$y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}$

I hope this helps!

5 0

3 years ago

Use the distributive property to remove the parenthesis (x+7)8

dimaraw [331]

8x+56

8(x)+8(7)= 8x+56

5 0

3 years ago

Read 2 more answers