The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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3x+7-5x=8
-2x+7=8
-2x=1
X=-1/2
y=3(-1/2)+7
y=-1.5+7
y=5.5
Answer:
A
Step-by-step explanation:
The diagonals of a parallelogram bisect each other. Hence, the two shorter sides created on diagonal RT ("6x-7" and "x+28" ) are equal.
<em>We can set them equal and solve for x:</em>
<em>
</em>
<em />
<em>So the side length of 6x -7 is:</em>
<em>6(7)-7 = 35</em>
<em>and the side length of x + 28 is:</em>
<em>7 + 28 = 35</em>
<em />
<em>THus, the diagonal RT = 35 + 35 = 70 units</em>
<em />
<em>Answer choice A is right.</em>
Answer:
$100,700
Step-by-step explanation:
Given data
Principal= $38,000
rate= 8.25%
Time= 20 years
Applying the simple interest
A=P(1+rt)
substitute
A=38000(1+0.0825*20)
A=38000(1+1.65)
A=38000*(2.65)
A=$100,700
Hence in 20 years she will pay $100,700
225 3x5 is 15 and to the power of 2 is 15x15 so multiply and you get 225 hope it helps
