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3 years ago

O picatura de ulei cu volumul de 0,3 mm a format pe suprafata apei o pelicula cu aria de 300 cm Calculati grosimea peliculei

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

What did you misspell something or are you foreign

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Please help me! i'll mark you brainliest <br> 20 points, (maths)

marysya [2.9K]

Answer:

5/6 of the time or 50 minutes

Step-by-step explanation:

6 0

3 years ago

Situation The context you find yourself in is Electronics store owner. The name of your store is Electro Hut. As an owner you wa

denis-greek [22]

It would be 30%profit it in so it would be 3.00

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3 years ago

tammy buys candy that cost 5 dollars per pound. she will spend more than 40 dollars on candy. what are the possible numbers of p

maksim [4K]

Answer:

Step-by-step explanation:

x = number of pounds

5x<30

x<30/5

so she can buy X<6 pounds

7 0

3 years ago

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

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4 0

2 years ago

two points on the line are (-10,1) and (5,-5).if the coordinate of another point on the line is -3,what is the x-coordinate?

zlopas [31]

Answer:

x-coordinate = 0

Step-by-step explanation:

(-10,1) , (5,-5)

m = (y₂ - y₁)/(x₂ - x₁) = ( -5 - 1 ) / ( 5 - [-10] )

= -6 / ( 5 + 10)

= -6/15 = -2/5

y - y₁ = m (x - x₁)

y - 1 = (-2/5) ( x - [-10] )

y - 1 = (-2/5) ( x + 10 )

5 * (y -1) = -2 (x + 10)

5y - 5 = -2x -20

2x + 20 + 5y -5 = 0

2x + 5y + 15 = 0

Another point (a, -3) in on this line

2 * a + 5 * (-3) = -15

2a -15 = -15

2a = -15 +15

2a = 0

a = 0

x-coordinate = 0

6 0

3 years ago