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alexandr1967 [171]
3 years ago
11

What is the answer of this question

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>x^</em><em>2</em><em>-</em><em>1</em><em>.</em>

<em>EXPLANATION</em><em>:</em>

<em>To</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>polynomial</em><em>,</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>term</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>whole</em><em> </em><em>number</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

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3 years ago
Compare and contrast the absolute value of a real number to that of a complex number.
sveticcg [70]
The absolute value of a real number is a positive value of the number. Which means that the absolute value is the distance from zero of the number line. However, that of the complex numbers is the distance from the origin to the point in a complex plane. 
4 0
3 years ago
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Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

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2 years ago
The unknown measures of one triangle are about:
olga_2 [115]
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3 years ago
What is the slope of the line that passing through (-2, 4) and the origin.
S_A_V [24]

Answer:

slope= -2

Step-by-step explanation:

using \frac{y2-y1}{x2-x1} you plug in the values of (-2,4) and (0,0)

=\frac{0-4}{0-(-2)}

=\frac{-4}{2}

= -2

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3 years ago
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