If the bird species cannot adapt to eat a different source of food, this species of bird will most likely

1 answer:

4 0

The correct answer for the question that is presented is this one: "become extinct." If the bird species cannot adapt to eat a different source of food, this species of bird will most likely become extinct. Given the fact that the climate of the location changes very quickly, and the ecosystem becomes too cold for fruit trees to survive.

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Hematite is a naturally occurring mineral and a common form of iron ore. The following statements describe physical and chemical

Ivanshal [37]

The correct answer is option B.

The hematite particles rearrange to form a new substance. This is an example of a chemical change.

A chemical change is an irreversible process wherein the atoms of a substance undergoes a rearrangement that causes it to from a new substance with unique chemical properties.

3 0

4 years ago

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The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the

Ann [662]

Answer: The number of molecules inside the cell are $2.2\times 10^6$

Explanation:

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

$V=\pi r^2h$

where,

V = volume of cell = ?

r = radius of the celle = $\frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m$ (Conversion factor: $1m=10^6\mu m$ )

h = length of the cell = $3.1\mu m=3.1\times 10^{-6}m$

Putting values in above equation, we get:

$V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of biomolecule = 0.0051 M

Volume of solution = $7.033\times 10^{-18}m^3=7.033\times 10^{-15}L$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol$