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ioda
2 years ago
10

I

Chemistry
1 answer:
Evgen [1.6K]2 years ago
5 0

Answer:

k

Explanation:

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The human eye cannot see anything less than 40 micrometers in size. What is this length in meters?
Agata [3.3K]

Answer:

4e-5 is the length in meters

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6 0
2 years ago
What is the volume of 11.2 g of O2 at 7.78 atm and 415 K?
irina1246 [14]

Answer:

1.53 L

Explanation:

Step 1: Given data

  • Mass of oxygen (m): 11.2 g
  • Pressure (P): 7.78 atm
  • Temperature (T): 415 K
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L

3 0
3 years ago
The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o
Aleonysh [2.5K]

Answer: The questions looks unclear

Explanation: Periodic table is a table that contains elements arranged according to their increasing atomic number.

1. D belongs to group 4

E. Belongs to group 7

B belongs to group 1

A belongs to group 8. A noble gas.

R belongs to group 3. K belongs to group 6 C belongs to group 1. H belongs to group 8

3 0
3 years ago
The volume occupied by 0.25 mol of sulfur dioxide at rtp <br>​
Vladimir79 [104]

Answer:

V = 0.25 x 22.4 Liters

Explanation:

1 mole of any gas occupies 22.4 Liters at STP.

8 0
3 years ago
How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mas
dalvyx [7]
87+55=142
5+0=5
The answer is 142.5
8 0
2 years ago
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