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A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many

Igoryamba

Answer:

4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

Mass of Carbon = 35.8 g

Mass of Hydrogen = 3.72

Total Mass = 35.8 g + 3.72 = 39.52 g

%age of Carbon = (35.8 g ÷ 39.52 g) × 100

%age of carbon = 90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

Mass of Carbon = 4.82 g × (90.58 ÷ 100)

Mass of Carbon = 4.36 g

3 0

3 years ago

True or false: An element has two layers of electrons. The electrons in the outermost layer are called distance electrons.

valentinak56 [21]

Answer:

true

Explanation:

3 0

2 years ago

Read 2 more answers

In a 0.20 M solution, a weak acid is 3.0% dissociated.(a) Calculate the [H₃O⁺] , pH , [OH⁻], and pOH of the solution.

marin [14]

H₃O⁺ = $6.0$ × $10^{-3}$

OH = $1.7$ × $10^{-12}$

pH = 2.22

pOH = 11.78

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log( $a_{H+}$ )

Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.

Learn more about pH

brainly.com/question/12609985

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8 0

2 years ago

A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *

elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

P1 = initial pressure (kPa)
P2 = final pressure (kPa)
V1 = initial volume (L)
V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0

2 years ago

Draw the structural formula for 3-ethyl-3-methyl-1-pentyne. Click the "draw structure" button to launch the drawing utility.

Dima020 [189]

Answer:

See attached picture.

Explanation:

Hello,

In this case, for the given name, you can verify the structure on the attached picture, wherein you can see verify the presence of both the ethyl and methyl radicals at the third carbon as well as the triple bond at the first carbon.

Best regards.

6 0

3 years ago