1) How many 3/4 does it take to make 9/2?
Now look at this, 3/4 x 6 = 4 1/2. 4 1/2 is the same as 9/2
3/4 + 3/4 + 3/4 + 3/4 + 3/4 + 3/4 ---> takes 6, 3/4's to make 9/2
2) How many 3/4's go into 9/2?
This is the same question as the 1st one so the answer is 6 :)
3) 9/2 divided by 3/4 = ??
Use the KEEP< CHANGE< FLIP method, so it turns into I
I
I
I
9/2 x 4/3 < ------------------------------------- I
This is equal to 36/6 which is 6 :)
The answer is 6 for numbers 1, 2, and 3 :)
Tan205° = .466 tan55° = 1.428 tan25° = .466 -tan25° = " so just tan25
Answer:
Step-by-step explanation:
so i think if you land on heads it is more like a 70% chance of getting heads but then again it could be a 30% chance that you land on tails so if you land on head you get the Alsatian and tails you get a bulldog i hope you get the correct answer good luck
In simplest form it should be 5/7
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>
Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>
Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>
The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
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<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.