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tatyana61 [14]
3 years ago
7

What is the area of a perimeter with 12 cm?

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer:

shape name is it square or rectangle is needed to be told

Step-by-step explanation:

if it's square then area is 9cm^2

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The roots of the equation x2 - 14x + 48 = 0) are
MrRissso [65]

Answer:

{x}^{2}  - 14x + 48 = 0 \\  {x}^{2}  - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}

  • 4) <em><u>6 and 8</u></em> is the right answer.
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Write an equation of the line that passes through (1,2) and is parallel to the line y=-5x+4
valentinak56 [21]

Answer:

The equation of the Parallel line to the given line is  5x+y-7=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the line y = - 5x+4 and point (1,2)

The equation of the Parallel line to the given line is  ax+by+k=0

Given straight line  5x + y -4 =0

The equation of the Parallel line to the given line is  5x+y+k=0

This line passes through the point (1,2)

             5x+y+k=0

            5(1)+2+k=0

⇒              7+k=0

                   k =-7

<u>Final answer:-</u>

The equation of the Parallel line to the given line is  5x+y-7=0

7 0
2 years ago
What is the area of a sector with a central angle of (2pi/3) radians and a diameter of 12 in?
Stels [109]

Answer:

The area of the sector is 37.68\ in^{2}

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

we have

r=12/2=6\ in ----> the radius is half the diameter

substitute

A=(3.14)(6)^{2}

A=113.04\ in^{2}

step 2

Find the area of a sector with a central angle of (2pi/3)

Remember that

The area of 113.04\ in^{2} subtends a central angle of 2\pi \ radians

so

by proportion

Let

x----> the area of the sector

\frac{2\pi}{113.04}=\frac{(2\pi/3)}{x}\\ \\x=113.04*(2\pi/3)/(2\pi)\\ \\x=37.68\ in^{2}

8 0
3 years ago
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