<h2>
Answer:</h2>
a)
The probability that both televisions work is: 0.42
b)
The probability at least one of the two televisions does not work is:
0.5833
<h2>
Step-by-step explanation:</h2>
There are a total of 9 televisions.
It is given that:
Three of the televisions are defective.
This means that the number of televisions which are non-defective are:
9-3=6
a)
The probability that both televisions work is calculated by:

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.
and the total outcome is the selection of 2 televisions from a total of 9 televisions)
Hence, we get:

b)
The probability at least one of the two televisions does not work:
Is equal to the probability that one does not work+probability both do not work.
Probability one does not work is calculated by:

and the probability both do not work is:

Hence, Probability that atleast does not work is:
0.5+0.0833=0.5833
Answer:
b > 12.71
Step-by-step explanation:
Here in this question we have to solve the inequality equation given for b (An unknown variable}
Now, the equation is 
⇒ 
We are taking the base of the log here is 10.
So,
{Since
and
}
⇒ b > 12.71 (Approximate) (Answer)
All good and for number 6 you should draw an acute angle
Answer:
9x−c
= 9x + − c
=−c+9x
Step-by-step explanation: