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Ludmilka [50]
3 years ago
15

What is 3.6+2.5+1.2=?

Mathematics
1 answer:
trapecia [35]3 years ago
3 0

3.6+2.5+1.2= 7.3


I hope that's help !


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Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml
Temka [501]
<h2>Answer:</h2>

a)

The probability that both televisions work is:  0.42

b)

The probability at least one of the two televisions does not​ work is:

                          0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

          9-3=6

a)

The probability that both televisions work is calculated by:

=\dfrac{6_C_2}{9_C_2}

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42

b)

The probability at least one of the two televisions does not​ work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5

and the probability both do not work is:

=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833

Hence, Probability that atleast does not work is:

             0.5+0.0833=0.5833

4 0
3 years ago
Polynomials are written with the exponents of the terms in ___ order
exis [7]

Answer:

numeric maybe?

7 0
2 years ago
Solve the equation log^7b&gt;2
ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is (\log b)^{7} > 2

⇒ \log b > 2^{\frac{1}{7} }

We are taking the base of the log here is 10.

So, 10^{(\log b)} > 10^{2^{\frac{1}{7} } } {Since 10^{\log x} =x and e^{\ln x} = x}

⇒ b > 12.71 (Approximate) (Answer)

3 0
3 years ago
Check this please I need grade
Elden [556K]
All good and for number 6 you should draw an acute angle
3 0
3 years ago
Evaluateing expressions 9x-c
lyudmila [28]

Answer:

9x−c

= 9x + − c

=−c+9x

Step-by-step explanation:

3 0
3 years ago
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