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Hitman42 [59]
3 years ago
11

What is the solution of the equation sqrt 2 x+4-sqrt x=2

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0
There are 2 answers to this 

x=0 
x=16
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What is the product of 127 and 32
Sedaia [141]
4,064 because product is when you multiply so 127 * 32

4 0
4 years ago
Alice is thinking of a number n that she wants her sister to guess. Her first clue is that two less than six times her number is
Alik [6]

Answer:

10 < 6n -2 ≤ 34

n= {3, 4, 5, 6}

Step-by-step explanation:

number

⇒ n

two less than six times the number

⇒ 6n -2

it is between ten and thirty-four (inclusive)

⇒ 10 < 6n -2 ≤ 34

we can solve it as:

  • 10 < 6n -2 ≤ 34     ⇒ add 2 to all sides
  • 12 < 6n ≤ 36          ⇒ divide by 6 all sides
  • 2 < n  ≤ 6
  • n= (2, 6]

or

  • n= {3, 4, 5, 6}

5 0
3 years ago
Solve the following system of equations algebraically.
Triss [41]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 12 , 15 )

Equation Form:  x = 12 , y = 15

Step-by-step explanation:

7 0
3 years ago
A straight line inserted at the origin terminates at the point (6, 7) as it sweeps out an angle θ in standard position. Which of
ELEN [110]
Since the line stops at the point (6, 7), then it means that the height of the triangle made is 7 units and the base is 6 units long.
An angle, θ, is made at the line that joins the origin and the point (6, 7).

tan \theta = \frac{opp}{adj}
tan \theta = \frac{height}{base} = \frac{7}{6}

Hence, tan \theta = \frac{7}{6}
6 0
3 years ago
Read 2 more answers
Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the c
MrMuchimi

Using the Poisson distribution, the probabilities are given as follows:

A. 0.0888 = 8.88%.

B. 0.1354 = 13.54%.

C. 0.8646 = 86.46%.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

Item a:

10 hours, 2 calls per hour, hence the mean is given by:

\mu = 2 \times 10 = 20.

The probability is P(X = 20), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888

Item b:

1 hour, hence the mean is given by:

\mu = 2

The probability is P(X = 0), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354

Item c:

The probability is:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

5 0
2 years ago
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