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motikmotik
3 years ago
10

three african elephants can weigh a total of 13,500 pounds. at this rate, how many do 2 african elephants weigh?

Mathematics
2 answers:
Taya2010 [7]3 years ago
8 0
Your answer is 6,750
lidiya [134]3 years ago
7 0

Answer:

Step-by-step explanation:

13500/3 = 4500

4500 x 2 = 9000

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Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)
damaskus [11]

The product is equal to zero if one of the factors is equal to zero.

Therefore:

y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}

5 0
4 years ago
In a woodworking class, you need to make five triangles out of plywood. Each triangle has a height of 6 inches and a base of 14
vampirchik [111]
The area of a triangle can be calculated through the equation,
                            A = bh / 2
where A is area, b is base, and h is height. 
Substituting the known values from the given above to the equation
                            A = (14 in)(6 in) / 2 = 42 in²
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                            total area = 5(42 in²) = 210 in²
Thus, the total area of the plywood needed is 210 in².
6 0
4 years ago
Read 2 more answers
Let x = a + bi and y = c + di and z = f + gi
ikadub [295]
True statements:
a) x + y = y + x  ⇒ commutative property of addition
b) (x * y) * z = x * (y * z) ⇒ associative property of multiplication
d) (x + y) + z = x + (y + z) ⇒ associative property of addition

False statements:
c) x - y = y - x  should be: x - y = - y + x
e) (x - y) - z = x - (y - z) should be: (x - y) - z = x - (y + z)
6 0
3 years ago
Read 2 more answers
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
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