I believe you have to do a cross product formula.
2174/x = 28.19/100
Answer:
A. 30 two-point questions and 10 four-point questions
Step-by-step explanation:
30 multiplied by 2 equals 60
10 multiplied by 4 equals 40
60 plus 40 equals 100 points which is the amount of points the test is worth as stated i the question.
30 plus 10 equals 40, which is the total amount of questions in the test as stated in the question.
12x^3-11x^2+9x+18 divided by 4x+3
put he division into fraction
12x^3-11x^2+9x+18/4 x +3
reduced fraction by 2
12x^3-11x^2+9x+9/2 x +3
calculate sum
12x^3-11x^2+27/2 x +3
that is your answer ^
hope this helps :)
The linear function is: g = 3n-2. Plug in values from -2 to 4 into n. Like so, G = 3(-2)-2 = g = -8. So, n(x) = -2 and g(y) = -8. And so on, and so on.
Basically, your n values are the x values.
The number you get out of the equation will be your y value.
Answer:
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola
y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width =
Height =
Width =√10 and Height 
Step-by-step explanation:
Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)
are (h,k) and (-h,k).
Hence, the area of the rectangle will be (h + h) × k
Therefore, A = h²k ..... (2).
Now, from equation (1) we can write k = 5 - h² ....... (3)
So, from equation (2), we can write
![A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}](https://tex.z-dn.net/?f=A%20%3Dh%5E%7B2%7D%20%5B5-h%5E%7B2%7D%20%5D%3D5h%5E%7B2%7D%20-h%5E%7B4%7D)
For, A to be greatest ,

⇒ ![h[10-4h^{2} ]=0](https://tex.z-dn.net/?f=h%5B10-4h%5E%7B2%7D%20%5D%3D0)
⇒ 
⇒ 
Therefore, from equation (3), k = 5 - h²
⇒ 
Hence,
Width = 2h =√10 and
Height = 