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Katarina [22]
3 years ago
15

Simplify the rational expression. State any restrictions on the variable.

Mathematics
2 answers:
german3 years ago
5 0
<span>Simplify the rational expression. State any restrictions on the variable. 


A. t + 4; t ≠ 8 B. - t + 4; t ≠ - 8 C. t - 4; t ≠ - 8 D. - t - 4; t ≠ 8
 I think it would be C. 


</span>
11111nata11111 [884]3 years ago
4 0
T^2 -4t -32 = (t+4)(t-8)

so

t^2 -4t -32
------------- 
      t-8

= (t+4)(t-8)
--------------
     t-8

= t+4

answer is <span>A. t + 4; t ≠ 8
</span>
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In a square with side length of 6, what is the distance between the center of the square and the center of the largest equilater
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Place the right angle at the origin. Short leg on x-axis.
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x = -4x/3 + 8
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8 0
3 years ago
What are the coordinates of the centroid of a triangle with vertices P(−4, −1) , Q(2, 2) , and R(2, −3) ?
Alenkasestr [34]

Answer:

(x,y)=(0,\frac{-2}{3})

Step-by-step explanation:

Given : Vertices of Triangle P(x_1,y_1)=(-4,-1) , Q(x_2,y_2)=(2, 2) and R(x_3,y_3)=(2,-3)

To find : Centroid of a triangle

The centroid of a triangle is the point of intersection of the three medians of the triangle.

The formula to calculate the centroid of a triangle is:

(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})

Where, x_1,x_2,x_3,y_1,y_2,y_3  are the coordinates of the centroid

Substituting the values in the formula gives us:

(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})

(x,y)=(\frac{-4+2+2}{3},\frac{-1+2-3}{3})

(x,y)=(\frac{0}{3},\frac{-2}{3})

Therefore, (x,y)=(0,\frac{-2}{3})

4 0
3 years ago
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What is the volume of a right circular cylinder with a radius of 4 m and a height of 4 m?
dybincka [34]
Cylinder volume = PI * radius^2 * height
cylinder volume = 3.14159 * 16 * 4
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5 0
3 years ago
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A scale reports a 15-pound weight as weighing 12.375 pounds. Which of the following is true?
rusak2 [61]

Answer:

C

Step-by-step explanation:

If it is accurate then it would have gotten the correct weight, but by going down to the thousandths it would be precise


4 0
3 years ago
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This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
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