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3 years ago

Given the arithmetic sequence an = −3 + 9(n − 1), what is the domain for n?

Mathematics

2 answers:

swat323 years ago

7 0

I believe that the answer is All integers where n $\geq$ 1

Nitella [24]3 years ago

3 0

Answer: The set of domain for n is $\{n\ \epsilon\ N:n\geq 1\}$

Step-by-step explanation:

Since we have given that

$a_n=-3+(n-1)9$

And it is the arithmetic sequence.

So, The domain of a function is the complete set of all the possible values of n (i.e. independent variables).

So, we can put the value of n : 1 and greater than 1.

So, the set of domain for n is given by

$\{n\ \epsilon\ N:n\geq 1\}$

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Problem solving your family has a rectangular pool that measures 18 feet by 9 feet. your family wants to put a deck around the p

tester [92]

Let w be the width of the deck. Then, using the total area, we get:
(9+2w)(18+2w)=400
4w²+54w-238=0
2w²+27w-119=0
(2w-7)(w+17)=0
w=-17 or 7/2
Using the positive value, we get a width of 3&1/2 ft. for the deck
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7 0

3 years ago

Identify the pairs of congruent angles and proportional sides in the following figures.

Vinvika [58]

Answer:

Step-by-step explanation:

congruent angles:

angle A = H

B = J

K = C

L = D

proportional side :

AB proportional HJ

AD proportional HL

JK proportional BC

KL proportional CD

hope it helps

if it does so then please mark me as brainliest

7 0

3 years ago

Area of a triangle 36 ft. By 41 1/2 ft.?

ziro4ka [17]

A=1/2bh A=1/2(36)(41.5) A=747 square feet

7 0

3 years ago

In order for the limit of F(X) to exist at x=a, which of the following must hold true

astra-53 [7]

Answer:

Step-by-step explanation:

Given: limit of f(x) exists at x = a

To choose: the correct option

Solution:

A limit is a value that a function approaches as the input approaches some value.

$\lim_{x\rightarrow a}f(x)=L$ means that as x approaches to value a then f(x) approaches to value L.

A limit of a function f(x) exists at x = a if $\lim_{x\rightarrow a^-}f(x)=\lim_{x\rightarrow a^+}f(x)=L$

So, option A. is correct.

7 0

3 years ago

Which values are in the solution set of the compound inequality? Check all that apply. 4(x + 3) ≤ 0 or x + 1 > 3 –6 –3 0 3 8

Colt1911 [192]

we have

$4(x + 3) \leq 0$ -------> inequality 1

$x + 1 > 3$ -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

case 1) x=-6

Substitute the value of x=-6 in the inequality 1

$4(-6 + 3) \leq 0$

$4(-3) \leq 0$

$-12 \leq 0$ -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 2) x=-3

Substitute the value of x=-3 in the inequality 1

$4(-3 + 3) \leq 0$

$4(0) \leq 0$

$0 \leq 0$ -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 3) x=0

Substitute the value of x=0 in the inequality 1

$4(0 + 3) \leq 0$