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Mamont248 [21]
3 years ago
5

Algebra 1

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

The expression is 4b^{6}c^{3} ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- In the exponent rules, we add the exponents when we multiply terms

 have same base

- Ex: a^{m}*a^{n}=a^{m+n}

- The volume of the rectangular box is the product of its three

 dimensions

* Lets solve the problem

- John buys a water tank from a company

- The  tank he buys has the dimensions b² by b^4 by 4c³

∵ The water tank is shaped a rectangular box

∵ The tank has dimensions b^{2},b^{4},4c^{3}

∵ The volume of the tank = L × W × H , where L , W , H are the

  dimensions of the tank

- Assume that L = b² , W = b^{4} and H = 4c³

∴ The volume of the tank = b² × b^{4} × 4c³

- b² and b^4 has the same base, then add its exponents

∴ The volume of the tank = b^{4+2} × 4c³

∴ The volume of the tank = b^{6} × 4c³

∴ The volume of the tank = 4b^{6}c^{3}

* The expression which represents the volume of the tank is:

  4b^{6}c^{3}

∴ The answer is the second expression

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