Question

Algebra 1

Answer 1

Answer:

The expression is $4b^{6}c^{3}$ ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- In the exponent rules, we add the exponents when we multiply terms

 have same base

- Ex: $a^{m}*a^{n}=a^{m+n}$

- The volume of the rectangular box is the product of its three

 dimensions

* Lets solve the problem

- John buys a water tank from a company

- The  tank he buys has the dimensions b² by b^4 by 4c³

∵ The water tank is shaped a rectangular box

∵ The tank has dimensions $b^{2},b^{4},4c^{3}$

∵ The volume of the tank = L × W × H , where L , W , H are the

  dimensions of the tank

- Assume that L = b² , W = $b^{4}$ and H = 4c³

∴ The volume of the tank = b² × $b^{4}$ × 4c³

- b² and b^4 has the same base, then add its exponents

∴ The volume of the tank = $b^{4+2}$ × 4c³

∴ The volume of the tank = $b^{6}$ × 4c³

∴ The volume of the tank = $4b^{6}c^{3}$

* The expression which represents the volume of the tank is:

  $4b^{6}c^{3}$

∴ The answer is the second expression