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olchik [2.2K]
3 years ago
5

What is the equation of the line that passes through (4, -1) and (-2, 3)?

Mathematics
1 answer:
salantis [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, - 1) and (x₂, y₂ ) = (- 2, 3)

m = \frac{3+1}{-2-4} = \frac{4}{-6} = - \frac{2}{3} , thus

y = - \frac{2}{3} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 3) , then

3 = \frac{4}{3} + c ⇒ c = 3 - \frac{4}{3} = \frac{5}{3}

y = - \frac{2}{3} x + \frac{5}{3} ← in slope- intercept form

Multiply through by 3 to clear the fractions

3y = - 2x + 5 ( add 2x to both sides )

2x + 3y = 5 ( subtract 5 from both sides )

2x + 3y - 5 = 0 ← in general form

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