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Lapatulllka [165]
3 years ago
12

The radius of a sphere is 9cm. Volume= Round to the nearest tenth

Mathematics
2 answers:
Serggg [28]3 years ago
6 0

Answer: 3053.63 sq. cm.

Step-by-step explanation:

Volume = 4/3π x r^3

= 4/3 x π x 9^3

= 4/3 x π x 729

= (4π x 729) / 3

= 4π x 243

= 972π

= 3053.63

Schach [20]3 years ago
5 0

Answer:

3053.6

Step-by-step explanation:

pls mark as brainliest

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PLS HELP ME 50 POINTS!!!!! I NEED AN ANSWER ASAP!!!!!!
Sholpan [36]

Answer:

They went up 16 levels.

Step-by-step explanation:

You can find that by finding the distance from -2 to 14.
To find the distance from two numbers, a and b, we can substitute both in the formula d = |b - a|, where d is the distance between them.

d = |14 - (-2)| \to |14 + 2|\to|16|\to16

4 0
11 months ago
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The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km
Otrada [13]

Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

13.42=lw

w=13.42/l

p = 2(l + w) \\ 16.6 = 2(l +  \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2}  + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l =  \frac{10.24}{2}  \\ l = 5.12km

Since you have found the value of the length you can find the value.of the width.

w =  \frac{13.42}{l}  \\ w =  \frac{13.42}{5.12}  \\ w = 2.62km

5 0
3 years ago
the mall is 84 meters long. the post office is 38 meters long. how much longer is the mall than the post office
Flauer [41]

Step-by-step explanation:

length of mall=84m

length of post office=38m

how much longer is the mall than the post office=84-38= 46m

7 0
3 years ago
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I am child in the family
uranmaximum [27]

Answer:

why this question ?!

giving points?!

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2 years ago
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Which of the following is not a factor of x^3 – 3x^2 – 4x + 12?
Slav-nsk [51]

Answer:

c. (x + 3)

Step-by-step explanation:

using factor theorem

if x - 3 is a factor then p(a) = 0

p(a)= x^3 - 3x^2 - 4x + 12

a.(x-3)

p(3) = (3)^3 - 3(3)^2 - 4(3) + 12

= 27 - 27 - 12 + 12

= 0

therefore x-3 is a factor

b.(x + 2)

p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12

= -8 -12 + 8 + 12

,= 0

therefore x + 2 is a factor

c.(x + 3)

p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12

= -27 -27 + 12 + 12

= -30

therefore x + 3 is not a factor

d.(x-2)

p(2) = (2)^3 - 3(2)^2 - 4(2) + 12

= 8 -12 - 8 + 12

= 0

therefore x - 2 is a factor

4 0
3 years ago
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