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neonofarm [45]
3 years ago
13

Point A (-7,-2) is rotated 270 counterclockwise and then shifted down 3 units. What are to coordinates of K’

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

Answer:

K'= (-2, 4)

Step-by-step explanation:

First we are going to rotate our point 270° counterclockwise.

The rule for a 270° counterclockwise rotation is (x,y)-->(y,-x), which means that we just need to interchange the coordinates of the point and change the sign of the x-coordinate:

(x,y)-->(y,-x)

(-7,-2)-->(-2,-7)

(-7,-2)-->(-2,-(-7))

(-7,-2)-->(-2,7)

Now, to shift the point 3 units down, we just need to subtract 3 units from the new y-coordinate of our resulting point form the previous procedure:

(x,y)-->(x,y-3)

(-2,7)-->(-2,7-3)

(-2,7)-->(-2,4)

We can conclude that the coordinates of K' are (-2, 4)

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I mark brainliest for all my questions that are answered right :) thx for helping me
allsm [11]
The correct answer is y= 0.513(1.833)^x


Explain


We will use the equation on this form

Y=ab^x

Let’s us plug in the coordinates of first point

(X, y) , ( 9, 120)

We will have

Y=ab^x

120= ab^9

Our equation for a will be

Ab^9 = 120

ab ^9 / b^9 = 120/ b^9


a = 120/ b^9

So will have


Y= 120/ b^9 • b^x

Then we will plug in coordinates for the second point


( x,y) = ( 10, 220)

We will have

Y= 120/b^9 • b^x

220 = 120/b^9 • b^10-9


220= 120b

Divide both side by 120

B= 11/6

B= 1.833333 = 1.833



Let’s plug in the value b=11/6 to our equation for a


A= 120/b^9

A= 120/ 11/6^9

A= 120/11^9/6^9


A=120 • 6^9 / 11^9

= 0.51285 which equal to 0.513



So therefore the answer is

Y= 0.513(1.833)^x


I hope this help you

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What is the slope of the graph of y=−8x+15 ?
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See the file attached (photo) above - That is the graph for (-(8*x))+15

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