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3 years ago

If you don't know, please don't answer.

Mathematics

2 answers:

Rasek [7]3 years ago

6 0

Answer:

C. 33

Step-by-step explanation:

Sample mean is right in the centre of the interval

Sample mean:

(25+41)/2

66/2

weeeeeb [17]3 years ago

3 0

The answer is c. Have a great day kids❤️❤️

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Rom4ik [11]

3 x 5 = 0 I don’t :)

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3 years ago

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Which of the following is true?

den301095 [7]

Answer:

0.3073> 0.3037

Step-by-step explanation:

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3 years ago

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If the average (arithmetic mean) of 10,20,30,40, and x is 60, what is the value of x

Lilit [14]

60 = (10 + 20 + 30 + 40 + x)/5

300 = 100 + x

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3 years ago

Find S18 for geometric series given a5=-6 and a2= -48

Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4

a2 = a1 r^(2-1)

-48 = a1 r

divide

-6 =a1 r^4

---------------- yields 1/8 = r^3 take the cube root or each side

-48 = a1 r 1/2 = r

an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1

an = -96 (1/2)^ (n-1)

the sum

Sn = a1[(r^n - 1/(r - 1)]

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4 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

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4 years ago

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