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djyliett [7]
3 years ago
9

The first term in the expansion of the binomial (3x + y)4

Mathematics
2 answers:
Lelechka [254]3 years ago
5 0
I don't know if i'm right or what because I haven't learned binomial in like almost 4 years. (3x+y)?
Dafna11 [192]3 years ago
4 0
81x^4 is the correct answer
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The perimeter of a quarter circle is 14.28 KM. What is the quarter circle's radius?
lawyer [7]
Circumference= 2πr
Circumference= perimeter

14.28km= 2(3.14)r
14.28= 6.2831853072r
divide both sides by 6.2831853072
2.27= r

ANSWER: The radius is 2.27km

Hope this helps! :)
3 0
3 years ago
How to solve 4+|7-m|=5
notka56 [123]
When
|a|=b
assume
a=b and -a=b
so

4+|7-m|=5
minus 4 from both sides
|7-m|=1
assume
7-m=1 and
-(7-m)=1

7-m=1
minus 7 both sidees
-m=-6
times -1 both sides
m=6

-(7-m)=1
distribute
-7+m=1
add 7 to both sides
m=8

m=6 and 8
4 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
3 years ago
Solve (f^2 g^3) (f^4 g^2)<br> -If F=2 and G=4
Kamila [148]

Answer:

The answer simplify is 16384

Step-by-step explanation:

8 0
3 years ago
Please look for the question in the picture.
Ymorist [56]

it will be c

as

negative with negative erased together

5 0
2 years ago
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