Answer:
4√3
Step-by-step explanation:
The distance formula applies. It tells you ...
distance = √((x2 -x1)² +(y2 -y1)²)
Filling in the given values, you have ...
distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)
= √((-4√2+4√2)² +(2√3 +2√3)²)
= √(0 + (4√3)²)
distance = 4√3
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We make use of the fact that ...
2 6/12 is the right answer
I'm assuming you're looking for the dimensions of the plot. I'm going with that. ;) If the length of the plot is 5 meters longer than the width, then L = w + 5. The area for a rectangle is L*w, and we have an area value of 20,000 so our formula is 20000=(w+5)(w) and
. We will bring the 20,000 over by subtraction and set the polynomial equal to 0 to factor and solve for w.
Solving for w we get values of w=138.9 and -143.9. Of course the 2 things in math that will never EVER be negative are time and distance/length, so -143.9 is out. Our width is 138.9 and the length is 138.9 + 5 so the length is 143.9. And there you go! Hope that's what you needed!
For one pair of socks you pay $12 plus $2 shipping.
Let's use x as the variable for how many pairs of socks someone might buy.
If someone buys 5 pairs of socks, they will pay $62. $12 * 5 + $2
So, we can write the expression as 12x + 2.
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
