log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
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Answer:
1. X axis, 8, 3
2. Y axis, 4,-9
Step-by-step explanation:
The rule of reflections that the place opposite of the axis is negative so:
The rule for x-axis reflection is (x,-y)
The rule for y-axis is (-x,y)
For the first one, x has remained the same, so that means it’s a x-axis reflection.
So change -3 to 3
Same for the next one.
-9 is not changed so that means it’s a y-axis reflection.
And the point is 4,-9
Answer:
246.76$
Step-by-step explanation:
199 x .24 =
47.76
199 + 47.76 =
246.76
Think through this one...
9:48 + 9 minutes = 9:57
9:57 + 30 minutes = 10:27
10:27 + 3 hours = 1:27 p.m.