3 years ago

Find the zeros of the polynomial 12x^2+31x+20

Mathematics

1 answer:

alexdok [17]3 years ago

8 0

Answer:

-5/4; -4/3

Step-by-step explanation:

12x^2 + 31x + 20 =

(4x + 5)(3x + 4) -->

x = -5/4 OR -4/3

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-1/2x+12=-16 1/2 help Plz I need it quick

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