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insens350 [35]
3 years ago
9

One shortcoming of rapid application development (RAD) is _____.

Computers and Technology
1 answer:
VladimirAG [237]3 years ago
8 0
One shortcoming of rapid application development (RAD) is a narrow focus, which might limit future development.
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The equation of certain traveling waves is y(x.t) = 0.0450 sin(25.12x - 37.68t-0.523) where x and y are in
NNADVOKAT [17]

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

5 0
3 years ago
The most direct way for Jonothan to gain on-the-jib experience and earn money while attending school is to apply for
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A part-time job would provide on-the-job experience while also giving him a flexible schedule competing with school.
4 0
3 years ago
Write a function called factor that determines for a pair of integers whether the second integer is a factor of the first. The f
Aleks04 [339]
<h2>Answer:</h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   //Declare the function factor

   //It returns either true or false, therefore the return type is boolean

   //It receives two arguments - a and b

   public static boolean factor(int a, int b){

       

       //Check if a is divisible by b.

       //Return true if yes

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       //With the variables, call the factor() method

       //If it returns true, print the adequate message

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       //If it returns false, print the adequate message

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

   

 }            // End of main method

   

}    // End of class declaration

==============================================================

<h2>Sample Output 1:</h2>

>> Enter the pair of numbers  separated by a space

8 4

>> 4 is a factor of 8

==============================================================

<h2>Sample Output 2:</h2>

>> Enter the pair of numbers  separated by a space

9 4

>> 4 is NOT a factor of 9

==============================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining every segment of the code. Kindly go through the comments for better understanding of the code.

For simplicity, the code is re-written as follows with little or no comments;

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   public static boolean factor(int a, int b) {

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

    }

   

}

3 0
3 years ago
You need to install a customized console on 10 computers. what is the best way to do that?
ICE Princess25 [194]
So you're going to simply create, copy, and paste!  You're going to create your first console on the first computer, and the you'll be left with a .mmc file which you're going to copy and paste to the other nine.  As long as you can get that file over through a shared server connection, you should be fine!
6 0
3 years ago
Write a program using integers userNum and x as input, and output userNum divided by x four times. Ex: If the input is: 2000 2
STatiana [176]

Answer:

// here is code in c++.

// include header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables to read input

   int userNum,x;

   cout<<"enter the value of userNum and x :";

   // read the input from user

   cin>>userNum>>x;

   // divide the userNum with x 4 times

   for(int a=0;a<4;a++)

   {

       userNum=userNum/x;

       cout<<userNum<<" ";

   }

       cout<<endl;

return 0;

}

Explanation:

Declare two variables "userNum" and "x". Read the value of these. Run a for loop 4 time and divide the "userNum" with "x" and print  the value of "userNum".

<u>Output:</u>

enter the value of userNum and x :2000 2                                                                                  

1000 500 250 125  

3 0
3 years ago
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