Answer:
B) f(x) = 3x² - 2x + 5
Step-by-step explanation:
To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.
A) f(x) = 3x² + 2x - 5
B) f(x) = 3x² - 2x + 5
C) f(x) = 2x² + 3x - 5
D) f(x) = 2x² - 2x + 5
A. 3(-2)² + 2(-2) - 5 =
3(4) - 4 - 5
12 - 4 - 5
12 - 9
= 3
B. 3(-2)² - 2(-2) + 5 =
3(4) + 4 + 5
12 + 9
= 21
C. 2(-2)² + 3(-2) -5 =
2(4) - 6 - 5
8 - 11
= - 3
D. 2(-2)² + 2(-2) + 5 =
2(4) - 4 + 5
8 - 4 + 5
8 + 1
= 9
Your correct answer is: B
2a + 3b = 6
5a + 2b = 4
We multiply the first equation by 5 and the second by 2 and and subtract the second from the first:
10a + 15b = 30
-10a -4b = -8
11b = 22
b = 2
2a + 3(2) = 6
2a = 0
a = 0
Checking,
5(0) + 2(2) = 4
4 = 4, true
Answer:
-9
Step-by-step explanation:
you're taking away 7 each time, so -2-7=-9
I hope you can understand what i wrote
Answer:
hello there,
the answer for this equation is:
The value of Start Fraction 6 Over x End Fraction + 2x2, when x = 3 is 20.
Step-by-step explanation:
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