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3 years ago

Please help!

Mathematics

1 answer:

viktelen [127]3 years ago

5 0

Slope intercept y=mx + b, add y to both sides in your equation. Y=4x, slope intercept. Graphing should be easy, just plug in x intercepts

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Match each term with its notation.

Ugo [173]

Answer:

_k_ The number of treatment conditions

_n_ The number of scores in each treatment.

_N_ The total number of scores in the entire study.

_T_ The sum of the scores for each treatment condition.

_G_ The sum of all of the scores in the research study.

_F_ The F-ratio

Step-by-step explanation:

These notations are ANOVA (Analysis of variance) notations, where

k is the number of treatment conditions

n is the number of scores in the treatment

N is the total number of scores in the entire study

T is the sum of scores for a specific treatment

G is the sum of all scores in the study

and F is the F-ratio.

Now, for the question, we will match each term with its notation

_k_ The number of treatment conditions

_n_ The number of scores in each treatment.

_N_ The total number of scores in the entire study.

_T_ The sum of the scores for each treatment condition.

_G_ The sum of all of the scores in the research study.

_F_ The F-ratio

7 0

3 years ago

What is the y-intercept for the function f(x) = 2 x 5^x + 4

lesya [120]

Answer:

Step-by-step explanation:

We can find y-intercept by substituting 0 for x in the equation.

So, we will have:

y=2*5^0+4=2*1+4=2+4=6

y intercept is 6

6 0

2 years ago

pls help me due today, i will give brainliest !!!

gayaneshka [121]

Answer:

c=38

Step-by-step explanation:

Substitute 6 for r and -2 for t in the formula given

c=rt^(2)-3t+8

c=6*(-2)^2-3*(-2)+8

c=6*4-3*-2+8

c=24+6+8

7 0

3 years ago

Given that x + y = 13 and xy = 24, find the distance from the point (x, y) to the origin.

boyakko [2]

Answer: Distance from the point (x, y) to the origin is approximately 11 units.

Step-by-step explanation: Given equations x+y=13 and xy =24.

Solving first equation for y, we get

y = 13-x.

Substituting y=13-x in second equation, we get

x(13-x)= 24.

13x -x^2=24.

-x^2+13x =24.

-x^2+13x -24=0.

Dividing each term by -1, we get

x^2-13x+24=0.

Applying quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-13,\:c=24:\quad x=\frac{-\left(-13\right)\pm \sqrt{\left(-13\right)^2-4\cdot \:1\cdot \:24}}{2\cdot \:1}$

$x=\frac{-\left(-13\right)+\sqrt{\left(-13\right)^2-4\cdot \:1\cdot \:24}}{2\cdot \:1}:\quad \frac{13+\sqrt{73}}{2} =10.77$

$x=\frac{-\left(-13\right)-\sqrt{\left(-13\right)^2-4\cdot \:1\cdot \:24}}{2\cdot \:1}:\quad \frac{13-\sqrt{73}}{2}=2.23$

Plugging x=10.77 in first equation

y= 13-10.77 = 2.23

and plugging x=2.23 in first equation, we get

y = 13-2.23 = 10.77.

Therefore, (x,y) are (10.77, 2.23) and (2.23, 10.77).

Now, we need to find the distance of (x,y) from origin (0,0).

Applying distance formula :

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(10.77-0\right)^2+\left(2.23-0\right)^2}$

$=10.9984\$

<h3>≈ 11 units.</h3><h3>Therefore, distance from the point (x, y) to the origin is approximately 11 units.</h3>

3 0

3 years ago

Please give me the correct answer :)

tekilochka [14]

Answer:

-20, -15, -13, -11, -10.

p≥−10

hope this helps! :)

8 0

2 years ago

Read 2 more answers