Answer:
1.31
Step-by-step explanation:
= 
^2 x 
^3 x 2.48
= 1.31 x 0.40 x 2.48
= 0.524 x 2.48
= 1.31
:)
Answer was verified and rounded
Answer:
Step-by-step explanation:
For #2, remember that 
, so 
Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=
. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number 
, where a and b are any numbers, the conjugate is always 
. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:
Our answer is (28-3i)/(26)!
Answer:
She walked 10 blocks
Step-by-step explanation:
Answer:
P(X > 5) = 0.1164 to 4 d.p.
The parameters are defined in the explanation.
Step-by-step explanation:
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of potential hires = 10
x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5
p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367
q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633
P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)
Inserting the parameters and computing the probabilities for each of those values of X,
P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.
Hope this Helps!!!
Answer:
Step-by-step explanation:
Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
r = linear correlation coeff = 0.952
H_0: r =0\\
H_1 :r\neq 0
(Two tailed test)
r difference = 0.952
n=8
Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496
Test statistic t = 0.952/0.12496 = 7.618
Alpha = 0.05
df = 6
p value = 0.000267
This implies H0 is rejected.
There exists a linear relation between the variables and r cannot be 0
0.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest size
