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2 years ago

Jeff drinks 2/3 of a glass of juice. write a fraction that is equivalent to 2/3

1 answer:

8 0

Some fractions that are equivalent to 2/3 are 4/6 and 6/9
to find equivalent fractions, you just have to reduce the fraction or multiply both the top and bottom numbers by the same number to increase the fraction.
2/3 is as reduced as it can be, though.

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PLEASEE HELP!!

Alex777 [14]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
quadratic equation word problems
solving quadratic

<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

<h3>tips and formulas:</h3>

<u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
<u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
<u>PEMDAS</u>

<h3>let's solve: </h3>

$step - 1 : \: define$

$- 4 {t}^{2} + 12t + 100 = 0$

$step - 2 : \\ divide \: both \: sides \: by \: - 4$

${t}^{2} - 3t - 25 = 0$

$step - 3 : \\ solve \: the \: quadratic$

$formula : \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \: - 25 \: respectively$

$t = \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 } }{2.1}$

$t = \frac{ 3± \sqrt{ 9 + 100} }{2}$

$t = \frac{3 + \sqrt{ 109 } }{2}$

$t = \frac{3 - \sqrt{ 109 } }{2}$

$t = 6.7 \\ t = - 3.7$

$as \: we \: know \: time \: cannot \: be \: negative$

$\huge \therefore \: t = 6.7$

5 0

2 years ago

2 questions, all help is welcomed, I am very desperate yall thanks~!

skad [1K]

The answer for question number 1 is : 2x + 4
and for question number 2 : 10

7 0

2 years ago

Help if you can do this please

olga nikolaevna [1]

Answer:

Step-by-step explanation:

a. Since the parabola is compressed by a factor of 1/3 we can state:

a parabola is written this way : y=(x-h)²+k
h stands for the translation to the left ⇒ 2*3=6
k for the units down ⇒4*3=12

So the equation is : y=(x-6)²+12

b.Here the parabola is stretched by a factor of 2 so we must multiply by 1/2

We khow that a parabola is written this way : y=(x-h)²+k
(h,k) are the coordinates of the vertex
the maximum value is 7*0.5=3.5
we khow tha the derivative of a quadratic function is null in the maximum value
so let's derivate (x-h)²+k= x²+h²-2xh+k
f'(x)= 2x-2h h is 1 since the axe of simmetry is x=1
f'(x)=2x-2 ⇒2x-2=0⇒ x= 1
Now we khow that 1 is the point where the derivative is null
f(1)=3.5
3.5=(x-1)²+k
3.5= (1-1)²+k⇒ k=3.5

So the equation is : y=(x-1)²+3.5

the maximum height is where the derivative equals 0

h= -5.25(t-4)²+86
h= -5.25(t²-8t+16)+86
h=-5.25t²+42t-84+86
h=-5.25t²+42t+2

Let's derivate it :

f(x)= -10.5t+42
-10.5t+42=0
42=10.5t
t= 42/10.5=4

When the height was at max t=4s

h(max)= -5.25(4-4)²+86 = 86 m

h was 86m

8 0

2 years ago

Telling of a classroom is 32 feet. The width is 75% of the lengt. Find the area of the classroom in square feet

Evgesh-ka [11]

The area of the classroom is 768 square feet

7 0

3 years ago

Identify a pair of parallel lines in the given figure.

Alenkasestr [34]

Parallel Lines: lines in a plane which do not meet. they do not intersect at any point, so your answer is B.

7 0

3 years ago