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Ivanshal [37]
4 years ago
12

A company rents out 15 food booths and 20 game booths at the county fair. The fee for a food booth is 100$ plus 5$ per day. The

fee for a game booth is 50$ plus $7 per day. The fair lasts for d days, and all the booths are rented for the entire time. Write and simplify an expression for the amount in dollars that the company is paid.
Mathematics
1 answer:
sineoko [7]4 years ago
8 0
105 times 15= 1575
57 times 20= 1140 
1140+1575= 2715 

(2715)(d)= x 

x being the total amount the company paid
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A sales clerk wants to predict the shoe sizes that will be sold this weekend for a new shoe that is going on sale. She uses her
Alenkinab [10]

Answer:

6/15=0.400

Step-by-step explanation:

Count all of the shoe sizes that are less than 7.5. (6) And then divide that number by 15 (the number of customers)

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1. A company has a cash portfolio measured in millions. The drift is 0.1 per month, variance is 0.16per month. The initial cash
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

From the information given:

The probability distribution at the end of 6 months is determined as follows:

After 6 months;

Mean of probability distribution =  value of Initial cash  + \alphaT  

=2.0 +(0.1 × 6)

=2.6

After 6 months;

The probability distribution's standard deviation is estimated by using the following formula:

Standard deviation:

=  b\sqrt{T}

= 0.4 \times \sqrt{6}

= 0.9798

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            2.6

Standard deviation     0.9798

Variance                      0.96

After 12 months, the probability distribution is as follows:

Mean = value of Initial cash  + \alphaT

= 2.0 +(0.1 × 12)

= 3.2

The standard deviation is:

The standard deviation of probability distribution = b \sqrt{T}

= 0.4 \times \sqrt{12}

= 1.3856

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            3.2

Sandard deviation      1.3856

Variance                      1.92

b)  

in 6-month distribution, the probability of the negative value of the cash position is as follows.

Now, for us to find the negative cash distribution;

We need to estimate the z -scores value.

The z-score inform us greatly on the concept of how far a particular data point is from the mean.

For a normal distribution;

z = \dfrac{x-\mu}{\sigma}

Here;

the value of x = zero as a result that if it exceeds zero. the cash position will be negative.

∴

z = \dfrac{x-\mu}{\sigma}

z = \dfrac{0 - 2.6}{0.9798}

z = -2.6536

Using the standard distribution tables, it is now possible to calculate that the likelihood N(-2.65) equals 0.004 or 0.4 percent.

As a result, there's a 0.4 percent chance of getting a negative cash balance after six months.

For 12 months distribution:

The Probability of negative cash position is calculated as follows:

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-3.2}{1.3856} \\ \\ z = -2.3094

Using the standard distribution tables,

N(-2.31) equals 0.0104 or 1.04 percent.

As a result, there's a 1.04 percent chance of getting a negative cash balance after 1 year  

c) To determine the time period over which the likelihood of achieving a negative cash condition is highest, it's necessary to examine the z-score more closely. Essentially, the z-score measures the difference between a given value(x) and the mean of all potential values (\mu), expressed in terms of the total set's standard deviation (\sigma)

This suggests that the higher the z-score, the greater the difference occurring between x and \mu, and thus the likelihood of receiving x is minimal. As a result, the best chance of finding a certain value is when the z-score is the lowest.

To do so, calculate the derivative of the z-score in relation to the time interval. The point where the derivative is equivalent to zero is where the z-scores are at their lowest.

The first step is to go over the z-score formula in more detail, as seen below.;

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-(initial \ value + \alpha T)}{b \sqrt{T}} \\ \\ z = \dfrac{-initial \ value }{b\sqrt{T}}-\dfrac{a \sqrt{T}}{b} \\ \\

Now, compute the derivative of this equation with respect to T as follows:

\dfrac{dz}{dT}= \dfrac{initial \ value \times T^{-\dfrac{3}{2}}}{2b} - \dfrac{aT^{-\dfrac{1}{2}}}{2b}

Now, figure out the value of T at which this derivative is equal to zero by substituting all values as follows:

0 = \dfrac{2.0 \times T^{-\dfrac{3}{2}}}{2\times 0.4}- \dfrac{0.1 \times T^{-\dfrac{1}{2}}}{2 \times 0.4} \\ \\  \\ 0.1 \times T^{-\dfrac{1}{2}}= 2.0 \times T^{-\dfrac{3}{2}} \\ \\  \\T = \dfrac{2}{0.1} \\ \\ \\ T = 20

As a result, the time period in which achieving a negative cash condition is = 20 months.

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