What is( -10a^5-2a^5+14a^5)(12a^5-6a-10a^3) using distributive and the area model.

1 answer:

8 0

$(-10a^5-2a^5+14a^5)(12a^5-6a-10a^3) \\ = 2a^5 (12a^5-6a-10a^3) \\ = 24a^{10} - 12a^6 - 20a^8$

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