Answer:
P = 238475 N
Q = 181125
Explanation:
From the diagram attached below,
For the bridge to be at equilibrium,
Sum of upward force = sum of downward force
P+Q = 400000+19600
P+Q = 419600.................. Equation 1
Taking moment about support A
sum of clockwise moment = sum of anti clockwise moment.
400000(10-3)+19600(8-3) = Q(20-6)
2800000+98000 = 16Q
2898000 = 16Q
Q = 2898000/16
Q = 181125 N.
Substitute the value of Q into equation 1
P+181125 = 419600
P = 419600-181125
P = 238475 N.
Hence, support A exert a force of 238475 N and support B exert a force of 181125 N
Find the amount of labor necessary to move an object along the specified orientated curve given the force field F. y = 3x2 on the parabola from (0, 0) to F = (y, x) (4, 48).
<h3>How can you determine the work a force field performs along a curve?</h3>
A variable force's infinitesimal work can be defined in terms of the force's components and the displacement along the path,
<h3>How do you assess the force field F's work?</h3>
(c) Next, determine the work that the force field F performed on the object to move it through the field by moving it along the vector d. W = F d is the formula for work.
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Correct option is B
1 kWh is equal to 3.6 × 10
6
1 Watt-sec is a Joule a watt expended for a second.
Because there’s 3600 seconds in an hour,
then 3600 Ws = 1 Wh = 3600 Joules = 3.6 kJ
so 1000 Wh = 1 kWh = 1000 × 3.6 kJ = 3.6 MJ = 3.6 × 10
6
The process is called neutralization.
Hope this helps!
The answer is c, because ball is falling so its gravitationl potential energy decreases, but it kinetic energy increases. Energy is always conserved.
