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nordsb [41]
1 year ago
13

Two objects are moving in the xy-plane. Object A has a mass of 3.2 kg and has a velocity = (2.3 m/s)i+ (4.2 m/s)j and object B h

as a mass of 2.9 kg and has a velocity = (-1.8 m/s)i + (2.7 m/s)j . What is the total momentum of the system?
Physics
1 answer:
prisoha [69]1 year ago
8 0

The total momentum of the system is 2.14i + 21.27j.

A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).

The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.

The total momentum of the system is defined as follows:

As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by

P = Pₓ + P'

where Pₓ is the x-component of momentum

P' is the y-component of the momentum

Also, we know that

P=mv

where m is mass

v is velocity

Thus,

P = Pₓ + P'

P = m₁vₓ + m₂v'

vₓ is the x-component of the velocity

v' is the y- component of the velocity

Given, m₁= 3.2kg

m₂ = 2.9kg

Now,

P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)

P = (7.36i + 13.44j) + (-5.22i + 7.83j)

P = 2.14i + 21.27j

Thus, the total momentum of the given system is 2.14i + 21.27j.

Learn more about the momentum here:

brainly.com/question/4956182

#SPJ1

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A crate falls from an airplane flying horizontally at an altitude of 2,000 m.
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20.2 seconds

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Find: t, the time it takes for the crate to land.

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4 years ago
A 2 kg and 2 meter long stick is held horizontally. A 4 kg mass is placed at 30 cm, and a 5 kg mass is placed at 75 cm. Determin
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Answer:

τ = 32.8635 N-m (counterclockwise)

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r = 0.10 m

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r₁ = (1.00-0.30)m = 0.70 m

m₂ = 5 Kg

r₂ = (0.90-0.75)m = 0.15 m

In order to determine the torque on the meterstick if it is received and allowed to pivot about the 90 cm mark (ypu can see the pic to understand the question), we apply:

τ = r₁*m₁*g + r₂*m₂*g - r*M*g = g*(r₁*m₁+r₂*m₂-r*M)

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